What is the best approach to solve Move Zeroes?

The optimal approach for Move Zeroes is the "Optimal — Two Pointers (In-Place)" technique. It runs in O(n) time and uses O(1) space. Use a slow pointer insertPos tracking where the next non-zero goes. Fast pointer i scans the array. When a non-zero is found, place it at insertPos and advance both. Then fill remaining positions with

What is the time complexity of Move Zeroes?

The optimal solution for Move Zeroes has a time complexity of O(n) and a space complexity of O(1), achieved using the Two Pointers pattern.

Is Move Zeroes a Easy LeetCode problem?

Yes, LeetCode #283 (Move Zeroes) is rated Easy. It uses the Two Pointers pattern and is commonly asked in interviews at Facebook, Microsoft, Bloomberg.

How to solve Move Zeroes in Python, Java, C++, and JavaScript?

LumiChats provides complete solutions for Move Zeroes in Python, Java, C++, and JavaScript, along with step-by-step visual animations and time/space complexity analysis. All solutions are free to view.

#283EasyTwo Pointers

Move Zeroes

Move all zeroes to the end while preserving non-zero element order.

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Problem Statement

Given an integer array nums, move all 0's to the end of it while maintaining the relative order of the non-zero elements. You must do this in-place.

Examples

Example 1

Input:nums = [0,1,0,3,12]

Output:[1,3,12,0,0]

Example 2

Input:nums = [0]

Output:[0]

Constraints

1 ≤ nums.length ≤ 10⁴
-2³¹ ≤ nums[i] ≤ 2³¹ − 1

Solutions

Extra Array

TimeO(n)SpaceO(n)

Copy non-zero elements to a new array, then fill the remaining positions with zeros, and copy back. Uses extra space.

Visual Animation

def moveZeroes(nums: list[int]) -> None:
    result = [x for x in nums if x != 0]
    result += [0] * (len(nums) - len(result))
    nums[:] = result

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